Grammatical updates for part 2

Reference Manual/part2.tex

@@ -8,7 +8,7 @@
 An extension by definition is the formal way of introducing new symbols in a mathematical theory.
 Theories can be extended into new ones by adding new symbols and new axioms to it. We're interested in a special kind of extension, called \textit{conservative extension}.
 \begin{defin}[Conservative Extension]
-A theory $\mathcal{T}_2$ is a conservative extension over a theory $\mathcal{T}_1$ if:
+A theory $\mathcal{T}_2$ is a conservative extension of a theory $\mathcal{T}_1$ if:
 \begin{itemize}
 	\item $\mathcal{T}_1 \subset \mathcal{T}_2$
 	\item For any formula $\phi$ in the language of $\mathcal{T}_1$, if $\mathcal{T}_2 \vdash 		\phi$ then $\mathcal{T}_1 \vdash \phi$
@@ -29,7 +29,7 @@ Moreover, in that case we require that
 $$
 \exists ! y. \phi_{y, x_1,...,x_k}
 $$
-is a theorem of $\mathcal{T}_1$
+is a theorem of $\mathcal{T}_1$.
 \end{itemize}
 \end{itemize}
 \end{defin}
@@ -38,7 +38,7 @@ We also say that a theory $\mathcal{T}_k$ is an extension by definition of a the
 
 For function definition, it is common in logic textbooks to only require the existence of $y$ and not its uniqueness. The axiom one would then obtain would only be $\phi[f(x_1,...,x_n)/y]$ This also leads to conservative extension, but it turns out not to be enough in the presence of axiom schemas (axioms containing schematic symbols).
 \begin{lemma}
-In ZF, an extension by definition without uniqueness doesn't necessarily yields a conservative extension if the use of the new symbol is allowed in axiom schemas.
+In ZF, an extension by definition without uniqueness doesn't necessarily yield a conservative extension if the use of the new symbol is allowed in axiom schemas.
 \end{lemma}
 \begin{proof}
 In ZF, consider the formula $\phi_c := \forall x. \exists y. (x \neq \emptyset) \implies y \in x$ expressing that nonempty sets contain an element, which is provable in ZFC.
@@ -54,8 +54,8 @@ For the definition with uniqueness, there is a stronger result than only conserv
 \begin{defin}
 A theory $\mathcal{T}_2$ is a fully conservative extension over a theory $\mathcal{T}_1$ if:
 \begin{itemize}
-\item It is conservative
-\item For any formula $\phi_2$ with free variables $x_1, ..., x_k$ in the language of $\mathcal{T}_2$, there exists a formula $\phi_1$ in the language of $\mathcal{T}_1$ with free variables among $x_1, ..., x_k$ such that
+\item it is conservative, and
+\item for any formula $\phi_2$ with free variables $x_1, ..., x_k$ in the language of $\mathcal{T}_2$, there exists a formula $\phi_1$ in the language of $\mathcal{T}_1$ with free variables among $x_1, ..., x_k$ such that
 $$\mathcal{T}_2 \vdash \forall x_1...x_k. (\phi_1 \leftrightarrow \phi_2)$$
 \end{itemize}
 \end{defin}
@@ -64,7 +64,7 @@ An extension by definition with uniqueness is fully conservative.
 \end{thm}
 The proof is done by induction on the height of the formula and isn't difficult, but fairly tedious.
 \begin{thm}
-If an extension $\mathcal{T}_2$ of a theory $\mathcal{T}_1$ with axiom schemas is fully conservative, then for any instance of the axiom schemas of an axiom schemas $\alpha$ containing a new symbol, $\Gamma \vdash \alpha$ where $\Gamma$ contains no axiom schema instantiated with new symbols.
+If an extension $\mathcal{T}_2$ of a theory $\mathcal{T}_1$ with axiom schemas is fully conservative, then for any instance of the axiom schemas containing a new symbol $\alpha$, $\Gamma \vdash \alpha$ where $\Gamma$ contains no axiom schema instantiated with new symbols.
 
 \end{thm}
 \begin{proof}